2x^2-13x+1952x=180

Solution for 2x^2-13x+1952x=180 equation:

2x^2-13x+1952x=180

We move all terms to the left:

2x^2-13x+1952x-(180)=0

We add all the numbers together, and all the variables

2x^2+1939x-180=0

a = 2; b = 1939; c = -180;
Δ = b2-4ac
Δ = 19392-4·2·(-180)
Δ = 3761161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1939)-\sqrt{3761161}}{2*2}=\frac{-1939-\sqrt{3761161}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1939)+\sqrt{3761161}}{2*2}=\frac{-1939+\sqrt{3761161}}{4}
$